The list() constructor, when executed without input arguments, returns an empty list.Īfter creating the empty list, we can append all the given lists to the created list using the append() method to create a list of lists in python as shown in the following code snippet. For this, you can either use the square bracket notation or the list() constructor. To create a list of lists using the append() method, we will first create a new empty list. The append() method, when invoked on a list, takes an object as input and appends it to the end of the list. We can also create a list of lists using the append() method in python. List of Lists Using the append() Method in Python In the above example, you can observe that we have created a list of lists using the given lists. For instance, if you have 5 lists and you want to create a list of lists from the given lists, you can put them in square brackets as shown in the following python code. To create a list of lists in python, you can use the square brackets to store all the inner lists. Here, myList contains five lists as its elements. Following is an example of a list of lists. ![]() Concatenate Two Lists of Lists in PythonĪ list of lists in python is a list that contains lists as its elements.Sorting List of Lists in Python Using the sorted() Function.Sort List of Lists in Python Using the sort() Method.Reversing the Order of Elements of Inner List in List of Lists in Python.Reverse the Order of Inner List in List of Lists in Python.Remove an Element From a List of Lists Using the remove() Method.Delete an Element From a List of Lists Using the pop() Method.Delete an Element From a List of Lists in Python.Access Elements in a List of Lists in Python.Create List of Lists Using List Comprehension in Python.List of Lists Using the append() Method in Python.did OP really want to set mismatches as '-'? Is No supposed to be an index or a separate column? etc.), but hopefully this answer will guide OP towards the desired result. There's a number of things that are unclear on the asking of this question (e.g. This results in the following output for print( df ): No Text matchedItem Next, I copy over the elements from column Text only for the rows identified in the mask variable. In other words, first I set '-' as the default value for all the elements in column matchedItem. Given the mask variable that OP had written, this can be done simply as such: df = '-' Next, OP indicated that there should be a new column called matchedItem, which duplicates the df.Text when there was a match and '-' when there was not a match. Mask = df.apply( lambda x: any( item for item in kpi if item.lower() = x ) )īasically I changed the item.lower() in x to item.lower() = x. I suspect, OP wanted that statement to be False, which meant it needs to be written as 'a' = 'ab' which would be false. The way OP wrote that line would match cases where the character a is in any part of the element. ![]() There is also a mask variable, which I am assuming was meant to catch all cases where the df.Text is equal to either 'a' or ' b'. In addition to the df file, OP has a kpi list consisting of 'a' and 'b'. ![]() However, I'm assuming OP has a dataframe setup something like this: import pandasĭata = ![]() The question is presented in a somewhat confusing fashion.
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